A Sample Af Liquid Acetone Is Place In A 25.0 Ml Flask And Vaporized By The Heating To 75\Xc2\Xb0c At 1.02 Atm.The Vapor Weights 5.87 G.Calculate The

A sample af liquid acetone is place in a 25.0 mL flask and vaporized by the heating to 75°C at 1.02 atm.the vapor weights 5.87 g.Calculate the number of moles of the acetone

Hello!

A sample af liquid acetone is place in a 25.0 mL flask and vaporized by the heating to 75 °C at 1.02 atm, the vapor weights 5.87 g. Calculate the number of moles of the acetone

We have the following data:

V (volume) = 25.0 mL → 0.025 L

n (number of mols) = ? (in mol)

T (temperature) = 75 ºC

First lets convert the temperature on the Kelvin scale, lets see:

TK = TºC + 273.15

TK = 75 + 273.15

TK = 348.15 → T (temperature) = 348.15

P (pressure) = 1.02 atm

R (gas constant) = 0.082 atm.L / mol.K

We apply the data above to the Clapeyron equation (gas equation), lets see:

P*V = n*R*T

1.02*0.025 = n*0.082*348.15

0.0255 = 28.5483\:n

28.5483\:n = 0.0255

n = \dfrac{0.0255}{28.5483}

n = 0.00089322306...

n \approx 0.000893\:mol \to \boxed{\boxed{n\approx 8.93*10^{-4}\:mol}}\end{array}}\qquad\checkmark

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I Hope this helps, greetings ... Dexteright02! =)


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